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$5.6$ litres of gas at STP are found to have a mass of $11 \mathrm{~g}$. The molecular mass of the gas is:

(A) $22 \mathrm{u}$

(B) 44 U

(C) $88 \mathrm{u}$

(D) $32 \mathrm{u}$

Solution —

moles of gas $=\frac{5.6}{22.4}=\frac{1}{4} \Rightarrow \frac{1}{4}=\frac{11}{\text { GMM }} \Rightarrow$ GMM $=44 \mathrm{~g} / \mathrm{mol}$

So, The correct option will be (B) 44u

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