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The sum and the multiplication of two numbers are 11 and 18 gradually. Find the sum of their inverse.

Solution

: Let the numbers are $x$ and $y$.

$$\begin{array}{c} \therefore \quad x+y=11 \\ x y=18 \end{array}$$

Dividing eqn. 1 by 2 ,

\begin{aligned} & \frac{x+y}{x y}=\frac{11}{18} \\ \therefore \quad & \frac{1}{y}+\frac{1}{x}=\frac{11}{18} ; \text { Ans. } \end{aligned}

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