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Calculate the concentration of a solution in volume per cent made when 56 g of water is mixed with 0.17 L of ethanol.

Solution-

Volume of water $=\frac{\text { mass }}{\text { density }}$ $=\frac{56 \mathrm{~g}}{1.0 \mathrm{~g} \mathrm{~cm}^{-3}}=56 \mathrm{~cm}^{3}=56 \mathrm{~mL}$

Volume of ethanol $=0.17 \mathrm{~L}=0.17 \times 1000 \mathrm{~mL}=170 \mathrm{~mL}$

$\therefore$ volume of solution $=(56+170) \mathrm{mL}=226 \mathrm{~mL}$

$\therefore$ concentration per cent by volume

$$=\frac{56}{226} \times 100=24.78 \%$$

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