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Find the area of the triangle whose base is 7.5 cm and corresponding altitude is 4 cm.

Solution

Here base of triangle $=7.5 \mathrm{~cm}$, height of triangle $=4 \mathrm{~cm}$

Area of triangle $=\frac{1}{2} \times$ base $\times$ height

$$\begin{array}{l} =\frac{1}{2} \times(7.5 \mathrm{~cm}) \times 4 \mathrm{~cm} \\ =15 \mathrm{~cm}^{2} \end{array}$$

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