A school team won 6 games this year against 4 games won last year. What is the percentage increase?
in Mathematics
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A school team won 6 games this year against 4 games won last year. What is the percentage increase ?
in Mathematics
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Solution:

 Increase in the number of wins $=6-4=2$

$\therefore$ Percentage increase $=\frac{\text { Increase in the number of wins }}{\text { Original number of wins }} \times 10$

$$

=\frac{2}{4} \times 100=50

$$

Hence increase in wins $=50 \%$.

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