32 views
A certain number of men complete a piece of work in 28 days. If there were 10 men more, the work could be finished in 8 days before (less), then how many men were originally there?

## 1 Answer

Best Answer

Solution :

Let there be $x$ men originally.

Now, $x$ men finish the work in 28 days

$\Rightarrow 1$ man can finish it in $28 x$ days Again, $(x+10)$ men finish the work in $(28-8)=20$ days

$\Rightarrow 1$ man finishes the work in

$20(x+10)$ days

From the question,

\begin{aligned} & 28 x=20(x+10) \\ \Rightarrow & 28 x=20 x+200 \\ \Rightarrow & 28 x-20 x=200 \\ \Rightarrow & 8 x=200 \\ \therefore & x=\frac{200}{8}=25 \text { men; Ans. } \end{aligned}

## Related Questions

1 Vote
1 Answer 48 Views
48 views
1 Vote
1 Answer 32 Views
1 Vote
1 Answer 56 Views
1 Vote
1 Answer 51 Views
51 views
2 Votes
1 Answer 36 Views
1 Vote
1 Answer 44 Views
44 views
0 Votes
1 Answer 42 Views
42 views
2 Votes
1 Answer 87 Views
2 Votes
1 Answer 40 Views
1 Vote
1 Answer 20 Views