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18 men can do a piece of work in 9 days. 27 men will finish the work in :

(a) 8 days

(b) 6 days

(c) 18 Soln. :

(d) $13 \frac{1}{2}$ days

Solution

$\because 18$ men can do a piece of work in

$\therefore 1 \mathrm{man}$ can do a piece of work in

9 days.

$\therefore 1$ man can do a piece of work in $9 \times 18$ days.

$\therefore 27$ men can do a piece of work in

$\frac{9 \times 18}{27}$ days

$=6$ days; Ans.

$\therefore$ Correct option is$(b)$

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