Reduce to their L.C.D. $\frac{5}{21}$ and $\frac{7}{12}$.
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Reduce to their L.C.D. $\frac{5}{21}$ and $\frac{7}{12}$.
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Solution

L.C.M. of the denominators i.e., 21 and $12=84$

$\therefore \quad \frac{5}{21}=\frac{5 \times 4}{21 \times 4}=\frac{20}{84}$

$\& \quad \frac{7}{12}=\frac{7 \times 7}{12 \times 7}=\frac{49}{84}$

$\therefore \quad$ The required fractions are $\frac{20}{84}$ and $\frac{49}{84}$; Ans.

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