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The average age of 50 persons of a group is 60 years. If 5 persons are excluded, then the average becomes 62 years. Find the average age of excluded persons.

Solution

Sum of the ages of 50

persons $=50 \times 60$

$=3000$ years

Sum of ages of remaining persons

$=45 \times 62=2790$ years

$\therefore \quad$ Required average age

$$\begin{array}{l} =\frac{3000-2790}{5} \\ =\frac{210}{5}=42 \text { years; Ans. } \end{array}$$

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