56 views
Ram can do a piece of work in 24 days. Shyam is $20 \%$ more efficient than Ram. Find the number of days taken by $B$.

Solution :

Let $A$ 's work $=$ work of $l$

man

$\therefore \quad B^{\prime}$ s work $=1+20 \%$ of 1

$$\begin{array}{l} =1+\frac{20 \times 1}{100} \\ =\frac{6}{5} \text { men's work } \end{array}$$

Now, $\because$ Ram (l person) can do 1 work in 2 days

$\therefore$ Shyam i.e., $\frac{6}{5}$ (person) can do

1 work in $\frac{24}{\frac{6}{5}}$ days

$$\begin{array}{l} =\frac{24 \times 5}{6} \\ =20 \text { days; Ans. } \end{array}$$

Trick: Reqired days

$$\begin{array}{l} =\frac{100 \times 24}{100+20} \\ =20 \text { days; Ans. } \end{array}$$

1 Vote
51 views
1 Vote
48 views
1 Vote