A bag contains rupees, fifty paise $\&$ twenty-five paise coins in the proportion $2: 6: 8$. If the total amount is Rs. 210 , then find the number of coins of each kind.
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A bag contains rupees, fifty paise $\&$ twenty-five paise coins in the proportion $2: 6: 8$. If the total amount is Rs. 210 , then find the number of coins of each kind.
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Solution

 Ratio of different coins

$$

=2: 3: 2

$$

$\therefore \quad$ Value of all rupee coins

$$

\text { = Rs. } \frac{210 \times 2}{7}=\text { Rs. } 60

$$

Value of all fifty-paise coins

$$

\text { = Rs. } \frac{210 \times 3}{7}=\text { Rs. } 90

$$

Value of all twenty-five paise coins $=$ Rs. $\frac{210 \times 2}{7}=$ Rs. 60

Hence, No. of rupee coins $=60$

No. of 50 -paise coins

$$

=90 \times 2=180

$$

No. of 25 -paise coins $=60 \times 4$

$$

=240

$$

$\therefore$ The number of each type of coins $=60,180,240$; Ans.

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