In a series LCR circuit, the voltage across the resistance, capacitance and inductance is \(10 \mathrm{~V}\) each.
in Physics
13 views
3 Votes
3 Votes

In a series LCR circuit, the voltage across the resistance, capacitance and inductance is \(10 \mathrm{~V}\) each. If the capacitance is short circuited, the voltage across the inductance will be

(a) \(10 \mathrm{~V}\)

(b) \(\frac{10}{\sqrt{2}} \mathrm{~V}\)

(c) \(10 \sqrt{2} \mathrm{~V}\)

(d) \(20 \mathrm{~V}\)

in Physics
by
3.3k Points

1 Answer

2 Votes
2 Votes
 
Best Answer

The correct option of this question will be (b).

Solution —

As $V_{R}=V_{L}=V_{C}=10 V$

$\therefore \quad R=X_{L}=X_{C}$ and $Z=R$

and $V=I R=10 V$

When the capacitor is short circuited, the impedance of the circuit is

$Z^{\prime}=\sqrt{R^{2}+X_{L}^{2}}=\sqrt{R^{2}+R^{2}}=\sqrt{2} R$

and the current in the circuit is

$I^{\prime}=\frac{V}{Z^{\prime}}=\frac{10 V }{\sqrt{2 R}}$

$\therefore$ The voltage across the inductance is

$V_{L}^{\prime}=I^{\prime} X_{L}=\left(\frac{10 V }{\sqrt{2} R}\right) R=\frac{10}{\sqrt{2}} V$

by
3.3k Points

Related Questions

3 Votes
3 Votes
1 Answer 9 Views
2 Votes
2 Votes
1 Answer 13 Views

Categories

2.1k Questions

1.8k Answers

0 Comments

17 Users