Two short dipoles $\mathrm{pk} \& \frac{\mathrm{p}}{2} \hat{\mathrm{k}}$ are located at $(0,0,0) \&(1 \mathrm{~m}, 0,2 \mathrm{~m})$ respectively. The resultant electric field due to the two dipoles at the point $(1 \mathrm{~m}, 0,0)$ is :
in Physics
20 views
0 Votes
0 Votes

Two short dipoles $\mathrm{pk} \& \frac{\mathrm{p}}{2} \hat{\mathrm{k}}$ are located at $(0,0,0) \&(1 \mathrm{~m}, 0,2 \mathrm{~m})$ respectively. The resultant electric field due to the two dipoles at the point $(1 \mathrm{~m}, 0,0)$ is :

(A) $\frac{9 p}{32 \pi \epsilon_{0}}$

(B) $\frac{-7 p}{32 \pi e_{0}}$

(C) $\frac{7 p}{32 \pi \epsilon_{0}}$

(D) none of these

in Physics
by
344 Points

1 Answer

0 Votes
0 Votes
 
Best Answer

The given point is at axis of $\frac{\vec{p}}{2}$ dipole and at equatorial line of $P$ dipole so total field at given point is.

$\vec{E}=-\frac{k \vec{P}}{(1)^{3}}+\frac{2 k(\vec{P} / 2)}{(2)^{3}}$

$=k \vec{P}\left(-1+\frac{1}{8}\right)=\frac{-7 \vec{P}}{32 \pi \pi_{0}}$

So, The correct option of this question is (B).

by
344 Points

Related Questions

Welcome To Informesia

Informesia Helps You To Prepare India's All States Board Exams (CBSE, ICSE, UP Board, BSEB, HPBOSE, RBSE, MSBSHSE) and Competitive Exam Like JEE (Main + Advanced), AIIMS, NEET, KVPY, NTSE, BITSAT, Olympiad, CLAT...etc.
For Any Query or Suggestion, Please Contact us on :
[email protected]

Connect us on Social Media