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An unknown stable nuclide after absorbing a neutron emits an electron, and the new nuclide splits spontaneously into two alpha particles. The unknown nuclide is :

(A) ${ }_{4} \mathrm{Be}^{9}$

(B) ${ }_{3} \mathrm{Li}^{7}$

(C) ${ }_{2} \mathrm{He}^{4}$

(D) ${ }_{5} \mathrm{~B}^{10}$

${ }_{3} Li ^{7}+{ }_{0} n ^{1} \longrightarrow{ }_{-1} e ^{0}+{ }_{2} He ^{4}$

Hence the unknown nuclide is ${ }_{3} Li ^{7}$.

So, The correct option of this question is (B).

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