11 views

What is the dimension of $\lambda$ in the given equation.

$N = N o e^{-\lambda_{t}}$, where

$N$ represents the number of radioactive atom present at any time and No is the number of atom orignally present.

The dimension of $\lambda$ in the given above equation will be $\left[ M ^{0} L ^{0} T ^{-1}\right]$.
by
4.3k Points

12 views
11 views
7 views
12 views
10 views