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Two balls A and B are thrown with speeds u and u/2 respectively. Both the balls cover the same horizontal distance before returning to the plane of projection. If the angle of projection of ball B is 15° with the horizontal, then the angle of projection of A is :

(A) (1/2) sin-1 (1/8)

(B) (1/4) sin-1 (1/8)

(C) (1/3) sin-1 (1/8)

(D) sin-1 (1/8)

The correct option is A.

Solution :

​​​​For A, R = $\frac{u^2 sin\theta}{g}$

For B, R = $\frac{u^2}{8g}$

Comparing; $sin2\theta = \frac 1 8$

$\Rightarrow\theta = \frac 1 2 sin^1\frac 1 8$

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